1004140311 has 4 divisors (see below), whose sum is σ = 1338853752. Its totient is φ = 669426872.

The previous prime is 1004140297. The next prime is 1004140327. The reversal of 1004140311 is 1130414001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1130414001 = 3 ⋅376804667.

It is a cyclic number.

It is not a de Polignac number, because 1004140311 - 2⁷ = 1004140183 is a prime.

It is a super-3 number, since 3×1004140311³ (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004140351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167356716 + ... + 167356721.

It is an arithmetic number, because the mean of its divisors is an integer number (334713438).

Almost surely, 2^1004140311 is an apocalyptic number.

1004140311 is a deficient number, since it is larger than the sum of its proper divisors (334713441).

1004140311 is an equidigital number, since it uses as much as digits as its factorization.

1004140311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334713440.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1004140311 is about 31688.1730461066. The cubic root of 1004140311 is about 1001.3782033496.

Adding to 1004140311 its reverse (1130414001), we get a palindrome (2134554312).

The spelling of 1004140311 in words is "one billion, four million, one hundred forty thousand, three hundred eleven".