10042325131 has 4 divisors (see below), whose sum is σ = 10049080032. Its totient is φ = 10035570232.

The previous prime is 10042325123. The next prime is 10042325147. The reversal of 10042325131 is 13152324001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13152324001 = 19 ⋅692227579.

It is a cyclic number.

It is not a de Polignac number, because 10042325131 - 2³ = 10042325123 is a prime.

It is a super-5 number, since 5×10042325131⁵ (a number of 51 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10042325231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3375220 + ... + 3378193.

It is an arithmetic number, because the mean of its divisors is an integer number (2512270008).

Almost surely, 2^10042325131 is an apocalyptic number.

10042325131 is a deficient number, since it is larger than the sum of its proper divisors (6754901).

10042325131 is an equidigital number, since it uses as much as digits as its factorization.

10042325131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6754900.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 10042325131 its reverse (13152324001), we get a palindrome (23194649132).

The spelling of 10042325131 in words is "ten billion, forty-two million, three hundred twenty-five thousand, one hundred thirty-one".