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100423422013 = 585117163463
BaseRepresentation
bin101110110000110110…
…0111101000000111101
3100121012200101102001111
41131201230331000331
53121131344001023
6114044530242021
710153405001005
oct1354154750075
9317180342044
10100423422013
1139653449352
1217567726311
139615461c05
144c093a1005
15292b4c800d
hex1761b3d03d

100423422013 has 4 divisors (see below), whose sum is σ = 100440591328. Its totient is φ = 100406252700.

The previous prime is 100423421993. The next prime is 100423422019. The reversal of 100423422013 is 310224324001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100423422013 - 213 = 100423413821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100423422019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8575881 + ... + 8587582.

It is an arithmetic number, because the mean of its divisors is an integer number (25110147832).

Almost surely, 2100423422013 is an apocalyptic number.

It is an amenable number.

100423422013 is a deficient number, since it is larger than the sum of its proper divisors (17169315).

100423422013 is an equidigital number, since it uses as much as digits as its factorization.

100423422013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17169314.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 100423422013 its reverse (310224324001), we get a palindrome (410647746014).

The spelling of 100423422013 in words is "one hundred billion, four hundred twenty-three million, four hundred twenty-two thousand, thirteen".

Divisors: 1 5851 17163463 100423422013