Base | Representation |
---|---|
bin | 10010101101001110… |
… | …00000010100110001 |
3 | 221220220200021012011 |
4 | 21112213000110301 |
5 | 131032002000423 |
6 | 4340320202521 |
7 | 503606043466 |
oct | 112647002461 |
9 | 27826607164 |
10 | 10043000113 |
11 | 42940146a3 |
12 | 1b43469441 |
13 | c40894723 |
14 | 6b3b5766d |
15 | 3dba53b0d |
hex | 2569c0531 |
10043000113 has 8 divisors (see below), whose sum is σ = 10128593376. Its totient is φ = 9957542400.
The previous prime is 10043000101. The next prime is 10043000129. The reversal of 10043000113 is 31100034001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10043000113 - 25 = 10043000081 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10043000093 and 10043000102.
It is not an unprimeable number, because it can be changed into a prime (10043000153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117798 + ... + 184288.
It is an arithmetic number, because the mean of its divisors is an integer number (1266074172).
Almost surely, 210043000113 is an apocalyptic number.
It is an amenable number.
10043000113 is a deficient number, since it is larger than the sum of its proper divisors (85593263).
10043000113 is a wasteful number, since it uses less digits than its factorization.
10043000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67775.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 10043000113 its reverse (31100034001), we get a palindrome (41143034114).
The spelling of 10043000113 in words is "ten billion, forty-three million, one hundred thirteen", and thus it is an aban number.
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