Base | Representation |
---|---|
bin | 101110110001000101… |
… | …1100111110010011101 |
3 | 100121020020111212012111 |
4 | 1131202023213302131 |
5 | 3121140423232113 |
6 | 114045414434021 |
7 | 10153533223564 |
oct | 1354213476235 |
9 | 317206455174 |
10 | 100431461533 |
11 | 39657a3a587 |
12 | 1756a362911 |
13 | 9617018320 |
14 | 4c0a494bdb |
15 | 292c06513d |
hex | 17622e7c9d |
100431461533 has 4 divisors (see below), whose sum is σ = 108156958588. Its totient is φ = 92705964480.
The previous prime is 100431461519. The next prime is 100431461549. The reversal of 100431461533 is 335164134001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 45000409689 + 55431051844 = 212133^2 + 235438^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100431461533 is a prime.
It is a super-4 number, since 4×1004314615334 (a number of 45 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100431461495 and 100431461504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100431461503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3862748508 + ... + 3862748533.
It is an arithmetic number, because the mean of its divisors is an integer number (27039239647).
Almost surely, 2100431461533 is an apocalyptic number.
100431461533 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
100431461533 is a deficient number, since it is larger than the sum of its proper divisors (7725497055).
100431461533 is an equidigital number, since it uses as much as digits as its factorization.
100431461533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7725497054.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 100431461533 its reverse (335164134001), we get a palindrome (435595595534).
The spelling of 100431461533 in words is "one hundred billion, four hundred thirty-one million, four hundred sixty-one thousand, five hundred thirty-three".
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