Base | Representation |
---|---|
bin | 101110110011010100… |
… | …0011001010000001011 |
3 | 100121102102222112210221 |
4 | 1131212220121100023 |
5 | 3121314031104120 |
6 | 114101042450511 |
7 | 10155430602466 |
oct | 1354650312013 |
9 | 317372875727 |
10 | 100506113035 |
11 | 39696098339 |
12 | 1758b363a37 |
13 | 9629625103 |
14 | 4c163682dd |
15 | 29338ae0aa |
hex | 1766a1940b |
100506113035 has 8 divisors (see below), whose sum is σ = 121281120720. Its totient is φ = 79955700384.
The previous prime is 100506113027. The next prime is 100506113063. The reversal of 100506113035 is 530311605001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100506113035 - 23 = 100506113027 is a prime.
It is a super-2 number, since 2×1005061130352 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56147772 + ... + 56149561.
It is an arithmetic number, because the mean of its divisors is an integer number (15160140090).
Almost surely, 2100506113035 is an apocalyptic number.
100506113035 is a deficient number, since it is larger than the sum of its proper divisors (20775007685).
100506113035 is a wasteful number, since it uses less digits than its factorization.
100506113035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112297517.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 100506113035 its reverse (530311605001), we get a palindrome (630817718036).
The spelling of 100506113035 in words is "one hundred billion, five hundred six million, one hundred thirteen thousand, thirty-five".
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