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100506113035 = 5179112297333
BaseRepresentation
bin101110110011010100…
…0011001010000001011
3100121102102222112210221
41131212220121100023
53121314031104120
6114101042450511
710155430602466
oct1354650312013
9317372875727
10100506113035
1139696098339
121758b363a37
139629625103
144c163682dd
1529338ae0aa
hex1766a1940b

100506113035 has 8 divisors (see below), whose sum is σ = 121281120720. Its totient is φ = 79955700384.

The previous prime is 100506113027. The next prime is 100506113063. The reversal of 100506113035 is 530311605001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100506113035 - 23 = 100506113027 is a prime.

It is a super-2 number, since 2×1005061130352 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56147772 + ... + 56149561.

It is an arithmetic number, because the mean of its divisors is an integer number (15160140090).

Almost surely, 2100506113035 is an apocalyptic number.

100506113035 is a deficient number, since it is larger than the sum of its proper divisors (20775007685).

100506113035 is a wasteful number, since it uses less digits than its factorization.

100506113035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112297517.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 100506113035 its reverse (530311605001), we get a palindrome (630817718036).

The spelling of 100506113035 in words is "one hundred billion, five hundred six million, one hundred thirteen thousand, thirty-five".

Divisors: 1 5 179 895 112297333 561486665 20101222607 100506113035