Base | Representation |
---|---|
bin | 101110110011011000… |
… | …0001110000110111010 |
3 | 100121102120211202221112 |
4 | 1131212300032012322 |
5 | 3121320042231123 |
6 | 114101154440322 |
7 | 10155454205525 |
oct | 1354660160672 |
9 | 317376752845 |
10 | 100508164538 |
11 | 396972696a1 |
12 | 1758bb930a2 |
13 | 9629b92b12 |
14 | 4c1673dbbc |
15 | 2933b66d78 |
hex | 1766c0e1ba |
100508164538 has 4 divisors (see below), whose sum is σ = 150762246810. Its totient is φ = 50254082268.
The previous prime is 100508164517. The next prime is 100508164579. The reversal of 100508164538 is 835461805001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 835461805001 = 138731 ⋅6022171.
It can be written as a sum of positive squares in only one way, i.e., 95476674049 + 5031490489 = 308993^2 + 70933^2 .
It is a super-2 number, since 2×1005081645382 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100508164495 and 100508164504.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25127041133 + ... + 25127041136.
Almost surely, 2100508164538 is an apocalyptic number.
100508164538 is a deficient number, since it is larger than the sum of its proper divisors (50254082272).
100508164538 is an equidigital number, since it uses as much as digits as its factorization.
100508164538 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50254082271.
The product of its (nonzero) digits is 115200, while the sum is 41.
Adding to 100508164538 its reverse (835461805001), we get a palindrome (935969969539).
The spelling of 100508164538 in words is "one hundred billion, five hundred eight million, one hundred sixty-four thousand, five hundred thirty-eight".
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