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1005143313511 = 2968350746873
BaseRepresentation
bin11101010000001110011…
…01011100110001100111
310120002110011110211020001
432220013031130301213
5112432013142013021
62045431221322131
7132422250124111
oct16500715346147
93502404424201
101005143313511
11358308218517
12142978566347
1373a27a24a0c
14369135723b1
151b22d07b091
hexea0735cc67

1005143313511 has 8 divisors (see below), whose sum is σ = 1041325854480. Its totient is φ = 969062267712.

The previous prime is 1005143313481. The next prime is 1005143313527. The reversal of 1005143313511 is 1153133415001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1005143313511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1005143313511.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1005143313211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25353630 + ... + 25393243.

It is an arithmetic number, because the mean of its divisors is an integer number (130165731810).

Almost surely, 21005143313511 is an apocalyptic number.

1005143313511 is a deficient number, since it is larger than the sum of its proper divisors (36182540969).

1005143313511 is an equidigital number, since it uses as much as digits as its factorization.

1005143313511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50747585.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 1005143313511 its reverse (1153133415001), we get a palindrome (2158276728512).

The spelling of 1005143313511 in words is "one trillion, five billion, one hundred forty-three million, three hundred thirteen thousand, five hundred eleven".

Divisors: 1 29 683 19807 50746873 1471659317 34660114259 1005143313511