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1005311401999 = 1952911126421
BaseRepresentation
bin11101010000100010011…
…10101010000000001111
310120002212212202121021121
432220101032222000033
5112432334204330444
62045500024141411
7132426360632032
oct16502116520017
93502785677247
101005311401999
11358394094923
12142a04907867
1373a537b7c68
143692ba09019
151b23cbd0084
hexea113aa00f

1005311401999 has 4 divisors (see below), whose sum is σ = 1058222528440. Its totient is φ = 952400275560.

The previous prime is 1005311401981. The next prime is 1005311402009. The reversal of 1005311401999 is 9991041135001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1005311401999 - 25 = 1005311401967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1005311401979) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26455563192 + ... + 26455563229.

It is an arithmetic number, because the mean of its divisors is an integer number (264555632110).

Almost surely, 21005311401999 is an apocalyptic number.

1005311401999 is a gapful number since it is divisible by the number (19) formed by its first and last digit.

1005311401999 is a deficient number, since it is larger than the sum of its proper divisors (52911126441).

1005311401999 is an equidigital number, since it uses as much as digits as its factorization.

1005311401999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52911126440.

The product of its (nonzero) digits is 43740, while the sum is 43.

The spelling of 1005311401999 in words is "one trillion, five billion, three hundred eleven million, four hundred one thousand, nine hundred ninety-nine".

Divisors: 1 19 52911126421 1005311401999