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10053150531 = 33351050177
BaseRepresentation
bin10010101110011011…
…01110011101000011
3221221121202221221120
421113031232131003
5131042101304111
64341321523323
7504061240524
oct112715563503
927847687846
1010053150531
114299817876
121b46943543
13c42a098a8
146b523a84b
153dc8ab406
hex25736e743

10053150531 has 4 divisors (see below), whose sum is σ = 13404200712. Its totient is φ = 6702100352.

The previous prime is 10053150529. The next prime is 10053150571. The reversal of 10053150531 is 13505135001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10053150531 - 21 = 10053150529 is a prime.

It is a super-2 number, since 2×100531505312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10053150511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1675525086 + ... + 1675525091.

It is an arithmetic number, because the mean of its divisors is an integer number (3351050178).

Almost surely, 210053150531 is an apocalyptic number.

10053150531 is a deficient number, since it is larger than the sum of its proper divisors (3351050181).

10053150531 is an equidigital number, since it uses as much as digits as its factorization.

10053150531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3351050180.

The product of its (nonzero) digits is 1125, while the sum is 24.

Adding to 10053150531 its reverse (13505135001), we get a palindrome (23558285532).

The spelling of 10053150531 in words is "ten billion, fifty-three million, one hundred fifty thousand, five hundred thirty-one".

Divisors: 1 3 3351050177 10053150531