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10053250030555 = 52010650006111
BaseRepresentation
bin1001001001001011010001…
…1001011001101111011011
31022121002012021120002020021
42102102310121121233123
52304203024001434210
633214222130011311
72055215623212634
oct222226431315733
938532167502207
1010053250030555
113226617611136
121164479116b37
1357c02c333044
1426a81934c88b
15126794cb9bda
hex924b4659bdb

10053250030555 has 4 divisors (see below), whose sum is σ = 12063900036672. Its totient is φ = 8042600024440.

The previous prime is 10053250030541. The next prime is 10053250030567. The reversal of 10053250030555 is 55503005235001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10053250030555 - 233 = 10044660095963 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10053250030555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1005325003051 + ... + 1005325003060.

It is an arithmetic number, because the mean of its divisors is an integer number (3015975009168).

Almost surely, 210053250030555 is an apocalyptic number.

10053250030555 is a deficient number, since it is larger than the sum of its proper divisors (2010650006117).

10053250030555 is an equidigital number, since it uses as much as digits as its factorization.

10053250030555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2010650006116.

The product of its (nonzero) digits is 56250, while the sum is 34.

Adding to 10053250030555 its reverse (55503005235001), we get a palindrome (65556255265556).

The spelling of 10053250030555 in words is "ten trillion, fifty-three billion, two hundred fifty million, thirty thousand, five hundred fifty-five".

Divisors: 1 5 2010650006111 10053250030555