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1005331312345 = 5201066262469
BaseRepresentation
bin11101010000100100110…
…10100110111011011001
310120002221021020011010211
432220102122212323121
5112432404303443340
62045502015011121
7132430022105503
oct16502232467331
93502837204124
101005331312345
113583a4353858
12142a0b509aa1
1373a57969629
143693050cd73
151b23e8145ea
hexea126a6ed9

1005331312345 has 4 divisors (see below), whose sum is σ = 1206397574820. Its totient is φ = 804265049872.

The previous prime is 1005331312259. The next prime is 1005331312373. The reversal of 1005331312345 is 5432131335001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 221151991824 + 784179320521 = 470268^2 + 885539^2 .

It is a cyclic number.

It is not a de Polignac number, because 1005331312345 - 225 = 1005297757913 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100533131230 + ... + 100533131239.

It is an arithmetic number, because the mean of its divisors is an integer number (301599393705).

Almost surely, 21005331312345 is an apocalyptic number.

It is an amenable number.

1005331312345 is a deficient number, since it is larger than the sum of its proper divisors (201066262475).

1005331312345 is an equidigital number, since it uses as much as digits as its factorization.

1005331312345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201066262474.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 1005331312345 its reverse (5432131335001), we get a palindrome (6437462647346).

The spelling of 1005331312345 in words is "one trillion, five billion, three hundred thirty-one million, three hundred twelve thousand, three hundred forty-five".

Divisors: 1 5 201066262469 1005331312345