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100534124711 = 313243036281
BaseRepresentation
bin101110110100001001…
…1010000000010100111
3100121111101200200121102
41131220103100002213
53121343213442321
6114103523110315
710156220650256
oct1355023200247
9317441620542
10100534124711
11396aa98a989
121759881239b
139632382077
144c19d7a79d
152936093c0b
hex17684d00a7

100534124711 has 4 divisors (see below), whose sum is σ = 103777161024. Its totient is φ = 97291088400.

The previous prime is 100534124707. The next prime is 100534124729. The reversal of 100534124711 is 117421435001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100534124711 - 22 = 100534124707 is a prime.

It is a super-2 number, since 2×1005341247112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100534129711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1621518110 + ... + 1621518171.

It is an arithmetic number, because the mean of its divisors is an integer number (25944290256).

Almost surely, 2100534124711 is an apocalyptic number.

100534124711 is a deficient number, since it is larger than the sum of its proper divisors (3243036313).

100534124711 is an equidigital number, since it uses as much as digits as its factorization.

100534124711 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3243036312.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 100534124711 its reverse (117421435001), we get a palindrome (217955559712).

The spelling of 100534124711 in words is "one hundred billion, five hundred thirty-four million, one hundred twenty-four thousand, seven hundred eleven".

Divisors: 1 31 3243036281 100534124711