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10053514113 = 33351171371
BaseRepresentation
bin10010101110011110…
…00111001110000001
3221221122110102200120
421113033013032001
5131042144422423
64341333410453
7504064313526
oct112717071601
927848412616
1010053514113
114299a45a55
121b46a99a29
13c42b06226
146b52d314d
153dc92dee3
hex2573c7381

10053514113 has 4 divisors (see below), whose sum is σ = 13404685488. Its totient is φ = 6702342740.

The previous prime is 10053514087. The next prime is 10053514123. The reversal of 10053514113 is 31141535001.

10053514113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31141535001 = 310380511667.

It is a cyclic number.

It is not a de Polignac number, because 10053514113 - 26 = 10053514049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10053514123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1675585683 + ... + 1675585688.

It is an arithmetic number, because the mean of its divisors is an integer number (3351171372).

Almost surely, 210053514113 is an apocalyptic number.

It is an amenable number.

10053514113 is a deficient number, since it is larger than the sum of its proper divisors (3351171375).

10053514113 is an equidigital number, since it uses as much as digits as its factorization.

10053514113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3351171374.

The product of its (nonzero) digits is 900, while the sum is 24.

The spelling of 10053514113 in words is "ten billion, fifty-three million, five hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 3351171371 10053514113