Base | Representation |
---|---|
bin | 10010101110100110… |
… | …00100101001011001 |
3 | 221221201102011121111 |
4 | 21113103010221121 |
5 | 131042431132103 |
6 | 4341411540321 |
7 | 504106166062 |
oct | 112723045131 |
9 | 27851364544 |
10 | 10054552153 |
11 | 429a594938 |
12 | 1b472ba6a1 |
13 | c430aa859 |
14 | 6b54c3569 |
15 | 3dca8686d |
hex | 2574c4a59 |
10054552153 has 4 divisors (see below), whose sum is σ = 10056533760. Its totient is φ = 10052570548.
The previous prime is 10054552049. The next prime is 10054552163. The reversal of 10054552153 is 35125545001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10054552153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10054552163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 983173 + ... + 993346.
It is an arithmetic number, because the mean of its divisors is an integer number (2514133440).
Almost surely, 210054552153 is an apocalyptic number.
It is an amenable number.
10054552153 is a deficient number, since it is larger than the sum of its proper divisors (1981607).
10054552153 is an equidigital number, since it uses as much as digits as its factorization.
10054552153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1981606.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 10054552153 in words is "ten billion, fifty-four million, five hundred fifty-two thousand, one hundred fifty-three".
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