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100553344141 = 263382332107
BaseRepresentation
bin101110110100101110…
…0100100010010001101
3100121112201212010201011
41131221130210102031
53121413124003031
6114105451045221
710156543215505
oct1355134442215
9317481763634
10100553344141
113970a817808
12175a3140811
139636351103
144c1c740a05
152937add6b1
hex176972448d

100553344141 has 4 divisors (see below), whose sum is σ = 100935676512. Its totient is φ = 100171011772.

The previous prime is 100553344123. The next prime is 100553344163. The reversal of 100553344141 is 141443355001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100553344141 - 29 = 100553343629 is a prime.

It is a super-2 number, since 2×1005533441412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100553444141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191165791 + ... + 191166316.

It is an arithmetic number, because the mean of its divisors is an integer number (25233919128).

Almost surely, 2100553344141 is an apocalyptic number.

It is an amenable number.

100553344141 is a deficient number, since it is larger than the sum of its proper divisors (382332371).

100553344141 is an equidigital number, since it uses as much as digits as its factorization.

100553344141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 382332370.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 100553344141 its reverse (141443355001), we get a palindrome (241996699142).

The spelling of 100553344141 in words is "one hundred billion, five hundred fifty-three million, three hundred forty-four thousand, one hundred forty-one".

Divisors: 1 263 382332107 100553344141