10055540403 has 24 divisors (see below), whose sum is σ = 14965030080. Its totient is φ = 6502343040.

The previous prime is 10055540399. The next prime is 10055540413. The reversal of 10055540403 is 30404555001.

10055540403 is a `hidden beast` number, since 100 + 5 + 554 + 0 + 4 + 0 + 3 = 666.

10055540403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10055540403 - 2² = 10055540399 is a prime.

It is a super-2 number, since 2×10055540403² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10055540413) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14923 + ... + 142596.

It is an arithmetic number, because the mean of its divisors is an integer number (623542920).

Almost surely, 2^10055540403 is an apocalyptic number.

10055540403 is a deficient number, since it is larger than the sum of its proper divisors (4909489677).

10055540403 is a wasteful number, since it uses less digits than its factorization.

10055540403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157739 (or 157736 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 27.

The spelling of 10055540403 in words is "ten billion, fifty-five million, five hundred forty thousand, four hundred three".