101000000018 has 4 divisors (see below), whose sum is σ = 151500000030. Its totient is φ = 50500000008.

The previous prime is 101000000011. The next prime is 101000000033. The reversal of 101000000018 is 810000000101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 91006598929 + 9993401089 = 301673^2 + 99967^2 .

It is a junction number, because it is equal to n+sod(n) for n = 100999999945 and 101000000008.

It is not an unprimeable number, because it can be changed into a prime (101000000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25250000003 + ... + 25250000006.

Almost surely, 2^101000000018 is an apocalyptic number.

101000000018 is a deficient number, since it is larger than the sum of its proper divisors (50500000012).

101000000018 is an equidigital number, since it uses as much as digits as its factorization.

101000000018 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50500000011.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 101000000018 its reverse (810000000101), we get a palindrome (911000000119).

The spelling of 101000000018 in words is "one hundred one billion, eighteen", and thus it is an aban number.