Base | Representation |
---|---|
bin | 10010110100000001… |
… | …10111101011110011 |
3 | 222001220010212010111 |
4 | 21122000313223303 |
5 | 131141112041430 |
6 | 4350120242151 |
7 | 505201352002 |
oct | 113200675363 |
9 | 28056125114 |
10 | 10100112115 |
11 | 43132827a5 |
12 | 1b5a610357 |
13 | c4c670002 |
14 | 6bb582c39 |
15 | 3e1a85c2a |
hex | 25a037af3 |
10100112115 has 8 divisors (see below), whose sum is σ = 12120697440. Its totient is φ = 8079714432.
The previous prime is 10100112101. The next prime is 10100112133. The reversal of 10100112115 is 51121100101.
10100112115 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10100112115 - 215 = 10100079347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10100112095 and 10100112104.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 137227 + ... + 197563.
It is an arithmetic number, because the mean of its divisors is an integer number (1515087180).
Almost surely, 210100112115 is an apocalyptic number.
10100112115 is a deficient number, since it is larger than the sum of its proper divisors (2020585325).
10100112115 is an equidigital number, since it uses as much as digits as its factorization.
10100112115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93821.
The product of its (nonzero) digits is 10, while the sum is 13.
Adding to 10100112115 its reverse (51121100101), we get a palindrome (61221212216).
The spelling of 10100112115 in words is "ten billion, one hundred million, one hundred twelve thousand, one hundred fifteen".
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