Base | Representation |
---|---|
bin | 1001001011111010010000… |
… | …0010000111011110001101 |
3 | 1022202120102201002102022222 |
4 | 2102332210002013132031 |
5 | 2310440222323144323 |
6 | 33251551014145125 |
7 | 2061500604403622 |
oct | 222764402073615 |
9 | 38676381072288 |
10 | 10100220131213 |
11 | 324452aa51a43 |
12 | 11715a73521a5 |
13 | 5835a6450304 |
14 | 26cbd34d2349 |
15 | 127ae36619c8 |
hex | 92fa408778d |
10100220131213 has 4 divisors (see below), whose sum is σ = 10100227888800. Its totient is φ = 10100212373628.
The previous prime is 10100220131207. The next prime is 10100220131219. The reversal of 10100220131213 is 31213102200101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is an interprime number because it is at equal distance from previous prime (10100220131207) and next prime (10100220131219).
It is a cyclic number.
It is not a de Polignac number, because 10100220131213 - 236 = 10031500654477 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10100220131191 and 10100220131200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10100220131219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1396145 + ... + 4706342.
It is an arithmetic number, because the mean of its divisors is an integer number (2525056972200).
Almost surely, 210100220131213 is an apocalyptic number.
It is an amenable number.
10100220131213 is a deficient number, since it is larger than the sum of its proper divisors (7757587).
10100220131213 is an equidigital number, since it uses as much as digits as its factorization.
10100220131213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7757586.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 10100220131213 its reverse (31213102200101), we get a palindrome (41313322331314).
The spelling of 10100220131213 in words is "ten trillion, one hundred billion, two hundred twenty million, one hundred thirty-one thousand, two hundred thirteen".
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