10100312113 has 8 divisors (see below), whose sum is σ = 10208707040. Its totient is φ = 9992004480.

The previous prime is 10100312083. The next prime is 10100312141. The reversal of 10100312113 is 31121300101.

10100312113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10100312113 - 2²⁵ = 10066757681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10100312093 and 10100312102.

It is not an unprimeable number, because it can be changed into a prime (10100312143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 225778 + ... + 266788.

It is an arithmetic number, because the mean of its divisors is an integer number (1276088380).

Almost surely, 2^10100312113 is an apocalyptic number.

It is an amenable number.

10100312113 is a deficient number, since it is larger than the sum of its proper divisors (108394927).

10100312113 is an equidigital number, since it uses as much as digits as its factorization.

10100312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43647.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10100312113 its reverse (31121300101), we get a palindrome (41221612214).

The spelling of 10100312113 in words is "ten billion, one hundred million, three hundred twelve thousand, one hundred thirteen".