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10100312232013 = 28964334871591
BaseRepresentation
bin1001001011111010100110…
…0001011101000001001101
31022202120200010101121212201
42102332221201131001031
52310440414412411023
633252004104201501
72061503103266233
oct222765141350115
938676603347781
1010100312232013
113244577a38703
121171612169291
135835bc559523
1426cc01828953
15127aeb7a5bad
hex92fa985d04d

10100312232013 has 4 divisors (see below), whose sum is σ = 10100347393248. Its totient is φ = 10100277070780.

The previous prime is 10100312231983. The next prime is 10100312232161. The reversal of 10100312232013 is 31023221300101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10100312232013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10100312272013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17146153 + ... + 17725438.

It is an arithmetic number, because the mean of its divisors is an integer number (2525086848312).

Almost surely, 210100312232013 is an apocalyptic number.

It is an amenable number.

10100312232013 is a deficient number, since it is larger than the sum of its proper divisors (35161235).

10100312232013 is an equidigital number, since it uses as much as digits as its factorization.

10100312232013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35161234.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10100312232013 its reverse (31023221300101), we get a palindrome (41123533532114).

The spelling of 10100312232013 in words is "ten trillion, one hundred billion, three hundred twelve million, two hundred thirty-two thousand, thirteen".

Divisors: 1 289643 34871591 10100312232013