1010032013 has 4 divisors (see below), whose sum is σ = 1024257888. Its totient is φ = 995806140.

The previous prime is 1010031989. The next prime is 1010032019. The reversal of 1010032013 is 3102300101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3102300101 = 27061 ⋅114641.

It is a cyclic number.

It is not a de Polignac number, because 1010032013 - 2¹⁸ = 1009769869 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1010031985 and 1010032003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1010032019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7112831 + ... + 7112972.

It is an arithmetic number, because the mean of its divisors is an integer number (256064472).

Almost surely, 2^1010032013 is an apocalyptic number.

It is an amenable number.

1010032013 is a deficient number, since it is larger than the sum of its proper divisors (14225875).

1010032013 is an equidigital number, since it uses as much as digits as its factorization.

1010032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14225874.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1010032013 is about 31781.0008180989. Note that the first 3 decimals coincide. The cubic root of 1010032013 is about 1003.3328838777.

Adding to 1010032013 its reverse (3102300101), we get a palindrome (4112332114).

The spelling of 1010032013 in words is "one billion, ten million, thirty-two thousand, thirteen".