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1010041213143 = 3336680404381
BaseRepresentation
bin11101011001010110010…
…01011101000011010111
310120120002111201220102010
432230223021131003113
5113022031022310033
62052001224315303
7132654522440634
oct16545311350327
93516074656363
101010041213143
1135a3a0a29a56
12143904912b33
1374328685a91
1436c59c5718b
151b418065863
hexeb2b25d0d7

1010041213143 has 4 divisors (see below), whose sum is σ = 1346721617528. Its totient is φ = 673360808760.

The previous prime is 1010041213141. The next prime is 1010041213183. The reversal of 1010041213143 is 3413121400101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1010041213143 - 21 = 1010041213141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1010041213141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168340202188 + ... + 168340202193.

It is an arithmetic number, because the mean of its divisors is an integer number (336680404382).

Almost surely, 21010041213143 is an apocalyptic number.

1010041213143 is a deficient number, since it is larger than the sum of its proper divisors (336680404385).

1010041213143 is an equidigital number, since it uses as much as digits as its factorization.

1010041213143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 336680404384.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1010041213143 its reverse (3413121400101), we get a palindrome (4423162613244).

The spelling of 1010041213143 in words is "one trillion, ten billion, forty-one million, two hundred thirteen thousand, one hundred forty-three".

Divisors: 1 3 336680404381 1010041213143