Base | Representation |
---|---|
bin | 101111000010001111… |
… | …1100111110110010011 |
3 | 100122201100201211212221 |
4 | 1132010133213312103 |
5 | 3123330311130003 |
6 | 114222501201511 |
7 | 10204023303403 |
oct | 1360437476623 |
9 | 318640654787 |
10 | 101007130003 |
11 | 3992298984a |
12 | 176ab100297 |
13 | 96a9375060 |
14 | 4c62b06803 |
15 | 29628787bd |
hex | 17847e7d93 |
101007130003 has 8 divisors (see below), whose sum is σ = 114502010000. Its totient is φ = 88330121568.
The previous prime is 101007129961. The next prime is 101007130009. The reversal of 101007130003 is 300031700101.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 101007130003 - 213 = 101007121811 is a prime.
It is a super-2 number, since 2×1010071300032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101007130009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204467628 + ... + 204468121.
It is an arithmetic number, because the mean of its divisors is an integer number (14312751250).
Almost surely, 2101007130003 is an apocalyptic number.
101007130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
101007130003 is a deficient number, since it is larger than the sum of its proper divisors (13494879997).
101007130003 is a wasteful number, since it uses less digits than its factorization.
101007130003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 408935781.
The product of its (nonzero) digits is 63, while the sum is 16.
Adding to 101007130003 its reverse (300031700101), we get a palindrome (401038830104).
The spelling of 101007130003 in words is "one hundred one billion, seven million, one hundred thirty thousand, three".
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