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101010122000000 = 2756163383809
BaseRepresentation
bin10110111101111001000000…
…011100001100011010000000
3111020122110210002001211102122
4112331321000130030122000
5101214422212213000000
6554455224234503412
730163511662364333
oct2675710034143200
9436573702054378
10101010122000000
112a2041745a4524
12b3b4531594b68
1344492a14762a5
141ad2cb769861a
15ba2789992085
hex5bde4070c680

101010122000000 has 448 divisors, whose sum is σ = 254053248076800. Its totient is φ = 40001817600000.

The previous prime is 101010121999999. The next prime is 101010122000041. The reversal of 101010122000000 is 221010101.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 124857999596 + ... + 124858000404.

Almost surely, 2101010122000000 is an apocalyptic number.

101010122000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101010122000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (127026624038400).

101010122000000 is an abundant number, since it is smaller than the sum of its proper divisors (153043126076800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101010122000000 is an frugal number, since it uses more digits than its factorization.

101010122000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1399 (or 1362 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 101010122000000 its reverse (221010101), we get a palindrome (101010343010101).

The spelling of 101010122000000 in words is "one hundred one trillion, ten billion, one hundred twenty-two million", and thus it is an aban number.