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10101100313 = 25513959663
BaseRepresentation
bin10010110100001001…
…01000111100011001
3222001222000001200102
421122010220330121
5131141340202223
64350153345145
7505212636023
oct113204507431
928058001612
1010101100313
114313898197
121b5aa081b5
13c4c927a45
146bb75d013
153e1bcd928
hex25a128f19

10101100313 has 4 divisors (see below), whose sum is σ = 10105062528. Its totient is φ = 10097138100.

The previous prime is 10101100309. The next prime is 10101100319. The reversal of 10101100313 is 31300110101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10101100313 - 22 = 10101100309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10101100294 and 10101100303.

It is not an unprimeable number, because it can be changed into a prime (10101100319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1977281 + ... + 1982382.

It is an arithmetic number, because the mean of its divisors is an integer number (2526265632).

Almost surely, 210101100313 is an apocalyptic number.

It is an amenable number.

10101100313 is a deficient number, since it is larger than the sum of its proper divisors (3962215).

10101100313 is an equidigital number, since it uses as much as digits as its factorization.

10101100313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3962214.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 10101100313 its reverse (31300110101), we get a palindrome (41401210414).

The spelling of 10101100313 in words is "ten billion, one hundred one million, one hundred thousand, three hundred thirteen".

Divisors: 1 2551 3959663 10101100313