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1010112021122 = 2505056010561
BaseRepresentation
bin11101011001011110101…
…11100100001010000010
310120120021102222022200212
432230233113210022002
5113022202134133442
62052012234114122
7132656342341121
oct16545727441202
93516242868625
101010112021122
1135a4279a2046
1214392457b942
137433a2482a9
1436c65409ab8
151b41e3a0a82
hexeb2f5e4282

1010112021122 has 4 divisors (see below), whose sum is σ = 1515168031686. Its totient is φ = 505056010560.

The previous prime is 1010112021101. The next prime is 1010112021197. The reversal of 1010112021122 is 2211202110101.

1010112021122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 761917748641 + 248194272481 = 872879^2 + 498191^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1010112021097 and 1010112021106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252528005279 + ... + 252528005282.

Almost surely, 21010112021122 is an apocalyptic number.

1010112021122 is a deficient number, since it is larger than the sum of its proper divisors (505056010564).

1010112021122 is an equidigital number, since it uses as much as digits as its factorization.

1010112021122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505056010563.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1010112021122 its reverse (2211202110101), we get a palindrome (3221314131223).

The spelling of 1010112021122 in words is "one trillion, ten billion, one hundred twelve million, twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 505056010561 1010112021122