101011304013 has 4 divisors (see below), whose sum is σ = 134681738688. Its totient is φ = 67340869340.

The previous prime is 101011303997. The next prime is 101011304039. The reversal of 101011304013 is 310403110101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101011304013 - 2⁴ = 101011303997 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101011303983 and 101011304001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101011304813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16835217333 + ... + 16835217338.

It is an arithmetic number, because the mean of its divisors is an integer number (33670434672).

Almost surely, 2^101011304013 is an apocalyptic number.

It is an amenable number.

101011304013 is a deficient number, since it is larger than the sum of its proper divisors (33670434675).

101011304013 is an equidigital number, since it uses as much as digits as its factorization.

101011304013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33670434674.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 101011304013 its reverse (310403110101), we get a palindrome (411414414114).

The spelling of 101011304013 in words is "one hundred one billion, eleven million, three hundred four thousand, thirteen".