10101433121111 has 4 divisors (see below), whose sum is σ = 10101473201712. Its totient is φ = 10101393040512.

The previous prime is 10101433121069. The next prime is 10101433121173. The reversal of 10101433121111 is 11112133410101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10101433121111 is a prime.

It is a super-3 number, since 3×10101433121111³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10101433121191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19659851 + ... + 20167116.

It is an arithmetic number, because the mean of its divisors is an integer number (2525368300428).

Almost surely, 2^{10101433121111} is an apocalyptic number.

10101433121111 is a deficient number, since it is larger than the sum of its proper divisors (40080601).

10101433121111 is an equidigital number, since it uses as much as digits as its factorization.

10101433121111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40080600.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 10101433121111 its reverse (11112133410101), we get a palindrome (21213566531212).

The spelling of 10101433121111 in words is "ten trillion, one hundred one billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred eleven".