10102033111 has 4 divisors (see below), whose sum is σ = 10102245400. Its totient is φ = 10101820824.

The previous prime is 10102033103. The next prime is 10102033133. The reversal of 10102033111 is 11133020101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10102033111 - 2³ = 10102033103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10102033091 and 10102033100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10102033141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885 + ... + 142153.

It is an arithmetic number, because the mean of its divisors is an integer number (2525561350).

Almost surely, 2^10102033111 is an apocalyptic number.

10102033111 is a deficient number, since it is larger than the sum of its proper divisors (212289).

10102033111 is an equidigital number, since it uses as much as digits as its factorization.

10102033111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212288.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10102033111 its reverse (11133020101), we get a palindrome (21235053212).

The spelling of 10102033111 in words is "ten billion, one hundred two million, thirty-three thousand, one hundred eleven".