10102043311 has 8 divisors (see below), whose sum is σ = 10125249264. Its totient is φ = 10078856640.

The previous prime is 10102043243. The next prime is 10102043317. The reversal of 10102043311 is 11334020101.

10102043311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10102043311 - 2¹⁹ = 10101519023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10102043317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1647331 + ... + 1653451.

It is an arithmetic number, because the mean of its divisors is an integer number (1265656158).

Almost surely, 2^10102043311 is an apocalyptic number.

10102043311 is a deficient number, since it is larger than the sum of its proper divisors (23205953).

10102043311 is an equidigital number, since it uses as much as digits as its factorization.

10102043311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9641.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10102043311 its reverse (11334020101), we get a palindrome (21436063412).

The spelling of 10102043311 in words is "ten billion, one hundred two million, forty-three thousand, three hundred eleven".