Search a number
-
+
101022002113 = 853118431421
BaseRepresentation
bin101111000010101100…
…0010110101111000001
3100122202101201102120211
41132011120112233001
53123343113031423
6114224152034121
710204263564334
oct1360530265701
9318671642524
10101022002113
113993031744a
12176b4092941
1396ac481416
144c64a9861b
152963d1510d
hex1785616bc1

101022002113 has 4 divisors (see below), whose sum is σ = 101140434388. Its totient is φ = 100903569840.

The previous prime is 101022002099. The next prime is 101022002183. The reversal of 101022002113 is 311200220101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21696406209 + 79325595904 = 147297^2 + 281648^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101022002113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101022002093 and 101022002102.

It is not an unprimeable number, because it can be changed into a prime (101022002183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59214858 + ... + 59216563.

It is an arithmetic number, because the mean of its divisors is an integer number (25285108597).

Almost surely, 2101022002113 is an apocalyptic number.

It is an amenable number.

101022002113 is a deficient number, since it is larger than the sum of its proper divisors (118432275).

101022002113 is an equidigital number, since it uses as much as digits as its factorization.

101022002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118432274.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 101022002113 its reverse (311200220101), we get a palindrome (412222222214).

The spelling of 101022002113 in words is "one hundred one billion, twenty-two million, two thousand, one hundred thirteen".

Divisors: 1 853 118431421 101022002113