101030300113 has 4 divisors (see below), whose sum is σ = 101078434800. Its totient is φ = 100982165428.

The previous prime is 101030300071. The next prime is 101030300177. The reversal of 101030300113 is 311003030101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101030300113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101030300093 and 101030300102.

It is not an unprimeable number, because it can be changed into a prime (101030300213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24064195 + ... + 24068392.

It is an arithmetic number, because the mean of its divisors is an integer number (25269608700).

Almost surely, 2^101030300113 is an apocalyptic number.

It is an amenable number.

101030300113 is a deficient number, since it is larger than the sum of its proper divisors (48134687).

101030300113 is an equidigital number, since it uses as much as digits as its factorization.

101030300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48134686.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 101030300113 its reverse (311003030101), we get a palindrome (412033330214).

The spelling of 101030300113 in words is "one hundred one billion, thirty million, three hundred thousand, one hundred thirteen".