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10103114121 = 33367704707
BaseRepresentation
bin10010110100011000…
…10100100110001001
3222002002210101002220
421122030110212021
5131142344122441
64350304444253
7505236024132
oct113214244611
928062711086
1010103114121
114314a431a1
121b5b619689
13c50181549
146bbb24c89
153e1e7a466
hex25a314989

10103114121 has 4 divisors (see below), whose sum is σ = 13470818832. Its totient is φ = 6735409412.

The previous prime is 10103114111. The next prime is 10103114123. The reversal of 10103114121 is 12141130101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10103114121 - 223 = 10094725513 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10103114121.

It is not an unprimeable number, because it can be changed into a prime (10103114123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683852351 + ... + 1683852356.

It is an arithmetic number, because the mean of its divisors is an integer number (3367704708).

Almost surely, 210103114121 is an apocalyptic number.

It is an amenable number.

10103114121 is a deficient number, since it is larger than the sum of its proper divisors (3367704711).

10103114121 is an equidigital number, since it uses as much as digits as its factorization.

10103114121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3367704710.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 10103114121 its reverse (12141130101), we get a palindrome (22244244222).

The spelling of 10103114121 in words is "ten billion, one hundred three million, one hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 3367704707 10103114121