1010341223433 has 6 divisors (see below), whose sum is σ = 1459381767194. Its totient is φ = 673560815616.

The previous prime is 1010341223431. The next prime is 1010341223443. The reversal of 1010341223433 is 3343221430101.

It is a happy number.

1010341223433 is a `hidden beast` number, since 1 + 0 + 1 + 0 + 3 + 4 + 1 + 223 + 433 = 666.

1010341223433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 1009729551609 + 611671824 = 1004853^2 + 24732^2 .

It is not a de Polignac number, because 1010341223433 - 2¹ = 1010341223431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1010341223397 and 1010341223406.

It is not an unprimeable number, because it can be changed into a prime (1010341223431) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56130067960 + ... + 56130067977.

Almost surely, 2^{1010341223433} is an apocalyptic number.

It is an amenable number.

1010341223433 is a deficient number, since it is larger than the sum of its proper divisors (449040543761).

1010341223433 is a wasteful number, since it uses less digits than its factorization.

1010341223433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112260135943 (or 112260135940 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1010341223433 its reverse (3343221430101), we get a palindrome (4353562653534).

The spelling of 1010341223433 in words is "one trillion, ten billion, three hundred forty-one million, two hundred twenty-three thousand, four hundred thirty-three".