101055149993 has 4 divisors (see below), whose sum is σ = 115491600000. Its totient is φ = 86618699988.

The previous prime is 101055149971. The next prime is 101055150017. The reversal of 101055149993 is 399941550101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 399941550101 = 47 ⋅8509394683.

It is a cyclic number.

It is not a de Polignac number, because 101055149993 - 2⁶ = 101055149929 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101055149963) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7218224993 + ... + 7218225006.

It is an arithmetic number, because the mean of its divisors is an integer number (28872900000).

Almost surely, 2^101055149993 is an apocalyptic number.

It is an amenable number.

101055149993 is a deficient number, since it is larger than the sum of its proper divisors (14436450007).

101055149993 is an equidigital number, since it uses as much as digits as its factorization.

101055149993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14436450006.

The product of its (nonzero) digits is 218700, while the sum is 47.

The spelling of 101055149993 in words is "one hundred one billion, fifty-five million, one hundred forty-nine thousand, nine hundred ninety-three".