10110001032013 has 4 divisors (see below), whose sum is σ = 10110070105660. Its totient is φ = 10109931958368.

The previous prime is 10110001031981. The next prime is 10110001032017. The reversal of 10110001032013 is 31023010001101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1779377248489 + 8330623783524 = 1333933^2 + 2886282^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110001032013 - 2⁵ = 10110001031981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10110001031984 and 10110001032002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110001032017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34316808 + ... + 34610161.

It is an arithmetic number, because the mean of its divisors is an integer number (2527517526415).

Almost surely, 2^{10110001032013} is an apocalyptic number.

It is an amenable number.

10110001032013 is a deficient number, since it is larger than the sum of its proper divisors (69073647).

10110001032013 is an equidigital number, since it uses as much as digits as its factorization.

10110001032013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69073646.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10110001032013 its reverse (31023010001101), we get a palindrome (41133011033114).

The spelling of 10110001032013 in words is "ten trillion, one hundred ten billion, one million, thirty-two thousand, thirteen".