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101100012113 = 1697220327043
BaseRepresentation
bin101111000101000000…
…1111100001001010001
3100122221211111202012002
41132022001330021101
53124023100341423
6114240020043345
710206231631622
oct1361201741121
9318854452162
10101100012113
1139970359521
1217716233555
1396c2695a99
144c711a3a49
15296aac4228
hex178a07c251

101100012113 has 8 divisors (see below), whose sum is σ = 101209249248. Its totient is φ = 100990836864.

The previous prime is 101100012029. The next prime is 101100012121. The reversal of 101100012113 is 311210001101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101100012113 - 226 = 101032903249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101100012094 and 101100012103.

It is not an unprimeable number, because it can be changed into a prime (101100012173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3724970 + ... + 3752012.

It is an arithmetic number, because the mean of its divisors is an integer number (12651156156).

Almost surely, 2101100012113 is an apocalyptic number.

It is an amenable number.

101100012113 is a deficient number, since it is larger than the sum of its proper divisors (109237135).

101100012113 is a wasteful number, since it uses less digits than its factorization.

101100012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30943.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 101100012113 its reverse (311210001101), we get a palindrome (412310013214).

The spelling of 101100012113 in words is "one hundred one billion, one hundred million, twelve thousand, one hundred thirteen".

Divisors: 1 1697 2203 27043 3738491 45891971 59575729 101100012113