Base | Representation |
---|---|
bin | 11101011011001000100… |
… | …11011100000110100011 |
3 | 10120122120100010000210110 |
4 | 32231210103130012203 |
5 | 113031012013211003 |
6 | 2052240321302403 |
7 | 133020345221511 |
oct | 16554423340643 |
9 | 3518510100713 |
10 | 1011000132003 |
11 | 35a843243984 |
12 | 143b31a94a03 |
13 | 7444c23b2a4 |
14 | 36d0b34d4b1 |
15 | 1b47232ea03 |
hex | eb644dc1a3 |
1011000132003 has 24 divisors (see below), whose sum is σ = 1372369787712. Its totient is φ = 662023952304.
The previous prime is 1011000132001. The next prime is 1011000132049. The reversal of 1011000132003 is 3002310001101.
1011000132003 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1011000132003 - 21 = 1011000132001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1011000132003.
It is not an unprimeable number, because it can be changed into a prime (1011000132001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4564876 + ... + 4781222.
It is an arithmetic number, because the mean of its divisors is an integer number (57182074488).
Almost surely, 21011000132003 is an apocalyptic number.
1011000132003 is a deficient number, since it is larger than the sum of its proper divisors (361369655709).
1011000132003 is an equidigital number, since it uses as much as digits as its factorization.
1011000132003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216831 (or 216764 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 1011000132003 its reverse (3002310001101), we get a palindrome (4013310133104).
The spelling of 1011000132003 in words is "one trillion, eleven billion, one hundred thirty-two thousand, three".
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