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101100032311 = 163620245597
BaseRepresentation
bin101111000101000001…
…0000001000100110111
3100122221211112202220011
41132022002001010313
53124023102013221
6114240020321051
710206232044535
oct1361202010467
9318854482804
10101100032311
1139970372713
1217716243187
1396c26a2035
144c711ab155
15296aaca1e1
hex178a081137

101100032311 has 4 divisors (see below), whose sum is σ = 101720278072. Its totient is φ = 100479786552.

The previous prime is 101100032279. The next prime is 101100032329. The reversal of 101100032311 is 113230001101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101100032311 - 25 = 101100032279 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101100032291 and 101100032300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101100036311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310122636 + ... + 310122961.

It is an arithmetic number, because the mean of its divisors is an integer number (25430069518).

Almost surely, 2101100032311 is an apocalyptic number.

101100032311 is a deficient number, since it is larger than the sum of its proper divisors (620245761).

101100032311 is an equidigital number, since it uses as much as digits as its factorization.

101100032311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 620245760.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 101100032311 its reverse (113230001101), we get a palindrome (214330033412).

The spelling of 101100032311 in words is "one hundred one billion, one hundred million, thirty-two thousand, three hundred eleven".

Divisors: 1 163 620245597 101100032311