Base | Representation |
---|---|
bin | 10110111111001100111010… |
… | …001011011000100100100111 |
3 | 111020222002022112212120100111 |
4 | 112333030322023120210213 |
5 | 101222411213034241203 |
6 | 555004443523553451 |
7 | 30203151324332416 |
oct | 2677147213304447 |
9 | 436862275776314 |
10 | 101100211243303 |
11 | 2a2393a462a408 |
12 | b409a9422b887 |
13 | 445492a913c4c |
14 | 1ad73c238747d |
15 | ba4cada9b26d |
hex | 5bf33a2d8927 |
101100211243303 has 4 divisors (see below), whose sum is σ = 101202229620928. Its totient is φ = 100998192865680.
The previous prime is 101100211243261. The next prime is 101100211243309. The reversal of 101100211243303 is 303342112001101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101100211243303 - 229 = 101099674372391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101100211243309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51009187326 + ... + 51009189307.
It is an arithmetic number, because the mean of its divisors is an integer number (25300557405232).
Almost surely, 2101100211243303 is an apocalyptic number.
101100211243303 is a deficient number, since it is larger than the sum of its proper divisors (102018377625).
101100211243303 is an equidigital number, since it uses as much as digits as its factorization.
101100211243303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102018377624.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 101100211243303 its reverse (303342112001101), we get a palindrome (404442323244404).
The spelling of 101100211243303 in words is "one hundred one trillion, one hundred billion, two hundred eleven million, two hundred forty-three thousand, three hundred three".
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