1011003203013 has 4 divisors (see below), whose sum is σ = 1348004270688. Its totient is φ = 674002135340.

The previous prime is 1011003202997. The next prime is 1011003203029. The reversal of 1011003203013 is 3103023001101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1011003202997) and next prime (1011003203029).

It is a cyclic number.

It is not a de Polignac number, because 1011003203013 - 2⁴ = 1011003202997 is a prime.

It is a super-4 number, since 4×1011003203013⁴ (a number of 49 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011003202983 and 1011003203001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011003203083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168500533833 + ... + 168500533838.

It is an arithmetic number, because the mean of its divisors is an integer number (337001067672).

Almost surely, 2^{1011003203013} is an apocalyptic number.

It is an amenable number.

1011003203013 is a deficient number, since it is larger than the sum of its proper divisors (337001067675).

1011003203013 is an equidigital number, since it uses as much as digits as its factorization.

1011003203013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337001067674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1011003203013 its reverse (3103023001101), we get a palindrome (4114026204114).

The spelling of 1011003203013 in words is "one trillion, eleven billion, three million, two hundred three thousand, thirteen".