Base | Representation |
---|---|
bin | 10010110101001101… |
… | …10000010010111011 |
3 | 222002120211102012000 |
4 | 21122212300102323 |
5 | 131201132341243 |
6 | 4351113152043 |
7 | 505351643652 |
oct | 113246602273 |
9 | 28076742160 |
10 | 10110043323 |
11 | 4318946206 |
12 | 1b619bb623 |
13 | c51739473 |
14 | 6bca0a199 |
15 | 3e28985d3 |
hex | 25a9b04bb |
10110043323 has 32 divisors (see below), whose sum is σ = 15862387200. Its totient is φ = 6350734368.
The previous prime is 10110043313. The next prime is 10110043357. The reversal of 10110043323 is 32334001101.
10110043323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10110043323 - 217 = 10109912251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10110043296 and 10110043305.
It is not an unprimeable number, because it can be changed into a prime (10110043303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79888 + ... + 163101.
It is an arithmetic number, because the mean of its divisors is an integer number (495699600).
Almost surely, 210110043323 is an apocalyptic number.
10110043323 is a deficient number, since it is larger than the sum of its proper divisors (5752343877).
10110043323 is a wasteful number, since it uses less digits than its factorization.
10110043323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 243088 (or 243082 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 10110043323 its reverse (32334001101), we get a palindrome (42444044424).
The spelling of 10110043323 in words is "ten billion, one hundred ten million, forty-three thousand, three hundred twenty-three".
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