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1011011341143 = 3337003780381
BaseRepresentation
bin11101011011001001111…
…10001100101101010111
310120122121010012111211210
432231210332030231113
5113031022400404033
62052241401432503
7133020542415306
oct16554476145527
93518533174753
101011011341143
1135a8495aa531
12143b3579b733
137445166430b
1436d0ca2a43d
151b4732e5d63
hexeb64f8cb57

1011011341143 has 4 divisors (see below), whose sum is σ = 1348015121528. Its totient is φ = 674007560760.

The previous prime is 1011011341091. The next prime is 1011011341169. The reversal of 1011011341143 is 3411431101101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1011011341143 - 29 = 1011011340631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011011381143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168501890188 + ... + 168501890193.

It is an arithmetic number, because the mean of its divisors is an integer number (337003780382).

Almost surely, 21011011341143 is an apocalyptic number.

1011011341143 is a deficient number, since it is larger than the sum of its proper divisors (337003780385).

1011011341143 is an equidigital number, since it uses as much as digits as its factorization.

1011011341143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337003780384.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 1011011341143 its reverse (3411431101101), we get a palindrome (4422442442244).

The spelling of 1011011341143 in words is "one trillion, eleven billion, eleven million, three hundred forty-one thousand, one hundred forty-three".

Divisors: 1 3 337003780381 1011011341143