101102000113 has 4 divisors (see below), whose sum is σ = 101103228148. Its totient is φ = 101100772080.

The previous prime is 101102000053. The next prime is 101102000147. The reversal of 101102000113 is 311000201101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311000201101 = 677 ⋅459379913.

It can be written as a sum of positive squares in 2 ways, for example, as 64684766224 + 36417233889 = 254332^2 + 190833^2 .

It is a cyclic number.

It is not a de Polignac number, because 101102000113 - 2⁹ = 101101999601 is a prime.

It is a super-2 number, since 2×101102000113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101102000113.

It is not an unprimeable number, because it can be changed into a prime (101102000173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 480906 + ... + 658387.

It is an arithmetic number, because the mean of its divisors is an integer number (25275807037).

Almost surely, 2^101102000113 is an apocalyptic number.

It is an amenable number.

101102000113 is a deficient number, since it is larger than the sum of its proper divisors (1228035).

101102000113 is an equidigital number, since it uses as much as digits as its factorization.

101102000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1228034.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 101102000113 its reverse (311000201101), we get a palindrome (412102201214).

The spelling of 101102000113 in words is "one hundred one billion, one hundred two million, one hundred thirteen", and thus it is an aban number.