101102113 has 4 divisors (see below), whose sum is σ = 115545280. Its totient is φ = 86658948.

The previous prime is 101102107. The next prime is 101102137. The reversal of 101102113 is 311201101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311201101 = 1913 ⋅162677.

It is a cyclic number.

It is not a de Polignac number, because 101102113 - 2⁵ = 101102081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101102113.

It is not an unprimeable number, because it can be changed into a prime (101102413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7221573 + ... + 7221586.

It is an arithmetic number, because the mean of its divisors is an integer number (28886320).

Almost surely, 2^101102113 is an apocalyptic number.

It is an amenable number.

101102113 is a deficient number, since it is larger than the sum of its proper divisors (14443167).

101102113 is an equidigital number, since it uses as much as digits as its factorization.

101102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14443166.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 101102113 is about 10054.9546493259. The cubic root of 101102113 is about 465.8578422132.

Adding to 101102113 its reverse (311201101), we get a palindrome (412303214).

The spelling of 101102113 in words is "one hundred one million, one hundred two thousand, one hundred thirteen".