10110213133 has 4 divisors (see below), whose sum is σ = 10152515520. Its totient is φ = 10067910748.

The previous prime is 10110213121. The next prime is 10110213137. The reversal of 10110213133 is 33131201101.

10110213133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10110213133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110213137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21150835 + ... + 21151312.

It is an arithmetic number, because the mean of its divisors is an integer number (2538128880).

Almost surely, 2^10110213133 is an apocalyptic number.

It is an amenable number.

10110213133 is a deficient number, since it is larger than the sum of its proper divisors (42302387).

10110213133 is an equidigital number, since it uses as much as digits as its factorization.

10110213133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42302386.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10110213133 its reverse (33131201101), we get a palindrome (43241414234).

The spelling of 10110213133 in words is "ten billion, one hundred ten million, two hundred thirteen thousand, one hundred thirty-three".