10110220131 has 64 divisors (see below), whose sum is σ = 15814656000. Its totient is φ = 5680730880.

The previous prime is 10110220079. The next prime is 10110220139. The reversal of 10110220131 is 13102201101.

It is a de Polignac number, because none of the positive numbers 2^k-10110220131 is a prime.

It is a super-2 number, since 2×10110220131² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10110220139) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5746830 + ... + 5748588.

It is an arithmetic number, because the mean of its divisors is an integer number (247104000).

Almost surely, 2^10110220131 is an apocalyptic number.

10110220131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10110220131 is a deficient number, since it is larger than the sum of its proper divisors (5704435869).

10110220131 is a wasteful number, since it uses less digits than its factorization.

10110220131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1984.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 10110220131 its reverse (13102201101), we get a palindrome (23212421232).

The spelling of 10110220131 in words is "ten billion, one hundred ten million, two hundred twenty thousand, one hundred thirty-one".