1011031310213 has 4 divisors (see below), whose sum is σ = 1011679824480. Its totient is φ = 1010382795948.

The previous prime is 1011031310203. The next prime is 1011031310227. The reversal of 1011031310213 is 3120131301101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011031310213 - 2⁴ = 1011031310197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011031310191 and 1011031310200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011031310203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324254795 + ... + 324257912.

It is an arithmetic number, because the mean of its divisors is an integer number (252919956120).

Almost surely, 2^{1011031310213} is an apocalyptic number.

It is an amenable number.

1011031310213 is a deficient number, since it is larger than the sum of its proper divisors (648514267).

1011031310213 is an equidigital number, since it uses as much as digits as its factorization.

1011031310213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 648514266.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1011031310213 its reverse (3120131301101), we get a palindrome (4131162611314).

The spelling of 1011031310213 in words is "one trillion, eleven billion, thirty-one million, three hundred ten thousand, two hundred thirteen".